php - Strange prepared statements error -


here how statement looks like.

               $stmt = $this->db->prepare("                         select q.id                          questions q                          left outer join (                         select max(chk_date) questions_last_chk_date                          last_check_date                          user_id = ?                          , chk_token=?) lcd                          on q.add_dt > lcd.questions_last_chk_date                         q.author_id<>?                 ") or die($this->db->error);                 $stmt->bind_param("isi", $_session["userid"], "q", $_session["userid"]) or die($stmt->error);

i got 2 questions

1) getting error message

fatal error: cannot pass parameter 3 reference

why error occurs? btw, know last_check_date table empty think it's not related problem.

2) on windows, getting error message table last_check_date doesn't exist, 100% know there no typo, , table exists. tried same query navicat - db amanger application , got result. when try php getting error. on remote linux server works, , getting error message in question 1. tried restart mysql service, rename other name , change name previous. no success! how can fix problem?

you have put q variable.

fyi, try not use string values equals tables alias or references. passing value of q when have table q alias. not error, maybe confusing in case need echo of query.


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