sql - How compare two int list, resultset? -


i have 2 list of integer in resultset in query, ex: list_1: 11,16,28... list_2 11,16,19.. how can compare 2 list in condition?? condition if list different, make select.

this code: 

    select cosechaanterior.c_fk_idboleta 'boleta_p16', cosechaanteriordestino.c_fk_idboleta 'boleta_p17' clt_cosechaanterior cosechaanterior inner join  clt_cosechaanteriordestino cosechaanteriordestino on cosechaanterior.si_fk_iddesglose = cosechaanteriordestino.si_fk_iddesglose inner join blt_boleta boleta on cosechaanterior.c_fk_idboleta = boleta.c_pk_idboleta  --boleta.c_pk_idboleta = 44990112--@id_boleta              (select si_fk_iddesglose            clt_cosechaanteriordestino cosechaanteriordestino            substring(cosechaanteriordestino.c_fk_idboleta,5,4) = '0112'            , cosechaanteriordestino.c_fk_idboleta = 44990112)              (select si_fk_iddesglose                                                                               clt_cosechaanterior cosechaanterior                                                                               substring(cosechaanterior.c_fk_idboleta,5,4)= '0112'                                                                               , cosechaanterior.c_fk_idboleta = 44990112)

you want join, rather in clause. little unclear question 2 lists are. answer gives general solution.

assume lists in two-column format (, ), list consists of multiple values. following query returns ids have same set of values:

select list1.id (<subquery 1>) list1 full outer join      (<subquery 2>) list2      on list1.id = list2.id ,         list1.val = list2.val group list1.id having max(case when list1.id null 1 else 0 end) = 0 ,        max(case when list2.id null 1 else 0 end) = 0

(this formulation assumes there no duplications in values.)

this doing full outer join , selecting ids have no null values on either side of join. null value generated on full outer join when elements not match.


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