web - Why the statement exec("php -l $file", $error, $exit) set $exit = 5 while there's no error? -


the file exists. i'm validating syntax of file statement.

exec("php -l $file", $error, $exit);

it supposed set $exit = 0 if there's no error. in other words, syntax in file right. in case, sets $exit 5 , $error empty array. wonder how case. in advance.

also, i'm using mamp. php5.3. $file hash string of file content. $code string of file content gotten file_get_contents() function. don't think $translatedfile , $error matter in question. 

function validatesyntax($code,$translatedfile,  &$error){         $translatedfile = $this->gettranslatedlanguagefile($translatedfile);         $file = 'cache/'.md5(time());         file_put_contents( $file, $code);         exec("php -l $file",$error,$exit);         foreach($error $k=>$v){             $error[$k] = str_replace($file, $translatedfile, $v);         }         unlink($file);         if($retcode==0)return true;         return false;     }

you quoting around of parameters, rather using quotes around command , passing last 2 arguments. looking for

exec("php -l $file", $error, $exit);

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