javascript - Jquery - Grab multiple selections' data in Jquery -


this originates my original question. i'm expanding on it.

html select options

    <select id="1d" name="camp" multiple="multiple">     <option data-url0="week_1" value="week 1">30th july</option>     <option data-url1="week_2" value="week 2">6th august</option>     </select>     <input type="hidden" name="camp_url0" id="1e">     <input type="hidden" name="camp_url1" id="1f">

jquery script i'm struggling with.

    $("#1d").on("change", function () {     var url1 = $(this).children(":selected").data("url0");     var url2 = $(this).children(":selected").data("url1");     $("#1e").val(url0);     $("#1f").val(url1); });

this code works beautifully (maybe not cleanest?), except 1 important issue. though multiple selector, whenever both options selected, 1 option marked :selected in dom, meaning 1 data-url{row_id} being inputted. need both, if both selected.

i hope makes sense. help.

upd:

add additional “routing” data html

<select id="1d" name="camp" size="5" multiple>     <option data-url="week_1" data-id="1e" value="week 1">30th july</option>     <option data-url="week_2" data-id="1f" value="week 2">6th august</option> </select>

and use it

$("#1d").on("change", function () {     $('input[type=hidden]').val('');      $('option:selected', this).each(function() {         $('#' + $(this).data('id')).val($(this).data('url'))     }) })

http://jsfiddle.net/5ctdc/1/

old:

just .map , array data.

$('option:selected', this).map(function() {     return $(this).data('url') })

["week_1", "week_2"]

http://jsfiddle.net/5ctdc/


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