Ruby warning: string literal in condition -


in seventh line, warning, "string literal in condition". warning mean, , how can resolve it?

   print 'continue use calculator?   y or n'    useragree = gets.chomp    if useragree == 'y' or 'y'         useragree = true    else         useragree = false    end

change

if useragree == 'y' or 'y'

to

if useragree == 'y' or useragree == 'y'

or, cleaner , clearer in opinion:

if useragree.upcase() == 'y'

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