php - get number day of month without Friday -


i need number of days in month, without example fridays.

$num = cal_days_in_month(cal_gregorian, $month, 2012); 

here can total number of days, need substract fridays count. how do it?

i found handy function here:

function num_days ($day, $month, $year) {      $day_array = array("mon" => "monday", "tue" => "tuesday", "wed" => "wednesday", "thu" => "thursday", "fri" => "friday", "sat" => "saturday", "sun" => "sunday");      $month_array = array(1 => "jan", "feb", "mar", "apr", "may", "jun", "jul", "aug", "sep", "oct", "nov", "dec");      /* * check our arguments valid. */      /* * $day must either full day string or 3 letter abbreviation. */      if (!(in_array($day, $day_array) || array_key_exists($day, $day_array))) {          return 0;      }      /* * $month must either full month name or 3 letter abrreviation */      if (($mth = array_search(substr($month,0,3), $month_array)) <= 0) {          return 0;      }      /* * fetch previous $day of $month+1 in $year; * give last $day of $month. */      /* * calculate timestamp of 01/$mth+1/$year. */       $time = mktime(0,0,0,$mth+1,1,$year);     $str = strtotime("last $day", $time);      /* * return nth day of month. */       $date = date("j", $str);      /* * if difference between $date1 , $date2 28 * there 5 occurences of $day in $month/$year, otherwise * there 4. */       if ($date <= 28) {          return 4;      } else {          return 5;      }  }  

usage:

echo date('t', strtotime("$month 2012")) - num_days('friday', $month, 2012);

provided $month full name of month (not number).


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