c - multidimensional array: incompatible type assignment -

i have declared array of known size,

typedef struct{   ......   char * buffer[height+1];    //height constant int   ......} args;  int main{  args * info;  info = malloc (sizeof(args));  char* output_buffer[width][height+1];    //width constant int >= 4  output_buffer[2] = malloc (sizeof(char)*char_per_line*(height+1)); // error same below  info->buffer = output_buffer[2];    // know it's wrong. incompatible types in assignment ....} 

numbers arbitrary , used illustration.

what doing assign address of output_buffer[width] info->buffer, , pass info argument thread, generates data array of size height+1; in each slot cstring of length char_per_line. cstrings stored in output_buffer[2].

i confused here isn't output_buffer[2] pointer of type char*[height+1]? why can't assign address of memory malloc it?

also, know cannot assign array array, how can code work in desired way? if solution use char** char*[height+1], how can access info->buffer[height], say?

thanks in advance!

according requirement specifying, need do

/* 2d array of pointers. */ char* output_buffer[width][height+1];   ( int =0; i< width; i++ )     ( int j=0; j <height+1; j++ )         output_buffer[i][j] = malloc (sizeof(char)*char_per_line*(height+1)); 

and then,

info->buffer[some_value] =  output_buffer[some_width][some_height];   

i confused here isn't output_buffer[2] pointer of type char*[height+1]? why can't assign address of memory malloc it?

malloc returns single dimensional pointer void* have noted, output_buffer[2] not single dimensional pointer. of type char*[height+1]. [] adds 1 more dimension apart *.