java - How does C# do runtime generics? -

one thing irritates me java awful implementation of compile-time translation of generic type arguments.

i can observe , understand c# implementation far better, i'm confused how works.

essentially, how can say:

t t = new t()

if don't know type of t , therefore don't know constructor argument requirements?

i can see

class<t> cl = t.class

t[] tarr = new t[0]

but don't see how can create new instance of t if don't know requirements of constructing it?

you can new t(); if t constrained have plain, parameterless public constructor, instance:

public class foo<t> t : new() {     private myt = new t(); }

additionally, there no way specify other sort of constructor exist. not possible:

// doesn't work public class foo<t> t : new(string, int) {     private myt = new t("foo", 5); }

to other points, how type of t @ runtime:

var ttype = typeof(t);

and creating array of t doesn't create instances (unless t value type, in case creates default value of type):

// space 32 t's, nothing in array. // if t value type, int instance,  // each 1 have default value (0 int, example) var arrayoft = new t[32];

Funaction