getting syntax error near unexpected token `;' in python -


i python novice please me out...

#!/usr/bin/python -tt  import sys import commands  def runcommands():   f = open("a.txt", 'r')   line in f:  # goes through text file line line     cmd = 'ls -l ' + line      print "printing cmd = " + cmd,     (status, output) = commands.getstatusoutput(cmd)   if status:    ## error case, print command's output stderr , exit       print "error"       sys.stderr.write(output)       sys.exit(1)   print output   f.close()  def main():   runcommands()  # standard boilerplate @ end of file call main() function. if __name__ == '__main__':   main()

i run follows:

$python demo.py sh: -c: line 1: syntax error near unexpected token `;' sh: -c: line 1: `; } 2>&1' error

running less $(which python) says:

#!/bin/sh bin=$(cd $(/usr/bin/dirname "$0") && pwd) exec -a "$0" "$bin/python2.5" "$@"

if remove for loop works fine

$cat a.txt dummyfile   $ls -l dummyfile -rw-r--r-- 1 blah blah ...................  $python demo.py printing cmd = ls -l dummyfile sh: -c: line 1: syntax error near unexpected token `;' sh: -c: line 1: `; } 2>&1' error

i using 'ls' showing problem. wanna use internal shell scripts have run python script in way only.

the problem caused line:

    cmd = 'ls -l ' + line

it should modified to:

    cmd = 'ls -l ' + line.strip()

when read line text file, read trailing \n. need strip works. getstatusoutput() doesn't trailing newline. see interactive test (which how verified it):

in [7]: s, o = commands.getstatusoutput('ls -l dummyfile')  in [8]: s, o = commands.getstatusoutput('ls -l dummyfile\n') sh: syntax error: ";" unexpected

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