C++: Make an array out of the elements of a two dimensional array that meet certain requirements -

i new multi-dimensional arrays, question struggling right following: have "maxn" number of days, , highest , lowest temperature recorded these days , have things data. 1 of these things determine days when temperature has been both below , above 0 (i.e.: lowest recorded temp below , highest above). program has output number of days when such thing occurred index of these days.

however, no matter loop use , how, mess , either absolutely irrelevant or infinite loop. here have far:

void abovebelow (int n, float days[maxn][2]{  int counter=0; float a[maxn];  (int i=0; i<n; i++){      (int j=0; j<n; j++){           if ((days[i][0]<0 && days[i][1]>0) || (days[i][1]<0 && days[i][0]>0)){            counter++;            i=a[j];       cout<<counter<<" "<<a[j]<<" ";    }     }  } 

you simple for-loop. why use 2 nested loops that?

and plus, if-condition modified to:

for (int i=0; i<n; i++) {     if (days[i][0]*days[i][1]<0) {         counter++;         cout<<"day "<<i+1<<endl;     } } cout<<"counter: "<<counter<<endl; 

ps:

1.i hope typo in code have pasted. there's syntax error in function declaration.

2.in standard c++, there's no vla (you unknowingly using compiler specific extra). unless maxn const (thanks, james), need to:

float *a = new fload[n];  //do stuffs here  delete[] a;