math - vectorial ODE in mathematica -


i want solve following equation in mathematica : 

dsolve[{x'[t] == a.x[t], x[0] == ( {{0},{0}} )}, x[t], t]

it system of 2 odes coupled matrix a, don't want put in form {{a,b},{c,d}} in order have output function of matrix exponential.

mathematica understands gives solution strangely expresed :

 {{x[t] ->       inversefunction[dot, 2, 2][a,           e^(t a.1)          inversefunction[inversefunction[dot, 2, 2], 2, 2][a, 0]]}}

where indeed uses matrix exponential, relies on strange notation inversefunction [...]

my question how rid of inversefunction notation have more readable expression. example have manner postulate a (2,2) matrix, invertible, inverse b?

if can hope better result maxima, please advise. lot help


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