oracle - Rank function in MySQL with Order By clause -


how (oracle) sql:

select a.*, rank() on (partition a.field1 order a.field2 desc) field_rank table_a order a.field1, a.field2

be translated mysql?

this question seems similar there no order in end of base query. also, matter ordered fields of partition?

according link gave should this: 

select    a.*, (              case a.field1              when @curtype              @currow := @currow + 1              else @currow := 1 , @curtype := a.field1 end           ) + 1 rank      table_a a,           (select @currow := 0, @curtype := '') r order  a.field1, a.field2 desc;

here 2 fiddles, 1 oracle , 1 mysql based on example link gave:

  1. oracle
  2. mysql

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