java - Adding hexadecimal numbers with a truncated result -


i need in java regarding memory location addition.

if current memory location @ fffffff8 , there offset of +10, in java value of 100000008 if want value 0000 0000 0000 0008 instead of 0000 0001 0000 0008, how should go doing , current code doing calculation optimized?

currently code using followed:

long = long.parselong("fffffff8",16) + long.parselong("10",16); string x = long.tohexstring(a);

since appears want 32-bit math, why using long in first place?

if use int, want:

int = 0xfffffff8 + 0x10;

will give 8.

and thomas said, unless you're being handed strings somwhere there no need use long.parselong() or integer.parseint() since can write numeric literals directly in hex form.


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